### Heritablity of Human Structural Connectomes ![:scale 40%](images/neurodata_blue.png) Jaewon Chung --- name:talk ### Outline - [Background](#defn) - [Measuring Heritability](#statistics) - [Discussion](#disc) --- name:defn ### Outline - Background - [Measuring Heritability](#statistics) - [Discussion](#disc) --- ### What is Heritability? - .ye[Heritability]: phenotypic variations due to genetic variations - understand effects of genes (+environment) on brain circuitry - understand neurologic diseases Question: Are the connectivity patterns in human brains heritable? --- ### What is a graph? (aka networks or connectomes) - Vertex = a region of interest - Edges = connectivity measure between a pair of vertices - Diffusion MRI = # of estimated neuronal fibers ![:scale 75%](images/herit/graph.png) --- ### Graph = Adjacency matrix ![:scale 100%](images/herit/representations.png) --- ### What data will we be using? - Human Connectome Project dataset - Identical twins (monozygotic), fraternal twins (dizygotic), siblings - $N\approx 1200$ individuals recruited - Most have diffusion and functional MRI --- name:statistics ### Outline - [Background](#defn) - Measuring Heritability - [Discussion](#disc) --- ### Hypothesis testing: distance correlation (DCorr) - Tests whether $X$ and $Y$ are independent. - Key idea: measures correlation between distance matrices $D^X$ and $D^Y$ - $D_{ij}^X = \delta_X(x_i, x_j), D_ij^Y = \delta_Y(y_i, y_j)$
Are differences in pairs of connectomes indepedent of genetics? - Need to compute $D^X$ and $D^Y$ --- ### Distance between graphs: Step 1 - Compute adj. spectral embedding (ASE) on graphs $G, H$ - Embeddings = latent positions - ASE$(G) = \hat{X}$, ASE$(H) = \hat{Y}$ - $\hat{X}, \hat{Y}\in\mathbb{R}^{N\times d}$
![:scale 80%](images/herit/ase.png)
--- ### Distance between graphs: Step 2 - Distance = Frobenius norm of difference in latent positions - $\delta_X(G, H) = ||\hat{X}R - \hat{Y}||_F$
![:scale 80%](images/herit/compute_distance.png)
High distance: pair of graphs are less similar (or more dissimilar) --- ### What is genetic distance? - Encode via labels - $\delta_Y(y_i, y_j) = 0$ if monozygotic (or self) - $\delta_Y(y_i, y_j) = 1$ if dizygotic/sibling - $\delta_Y(y_i, y_j) = 2$ if unrelated
![:scale 35%](images/herit/genetic_distance.png)
--- ### Are the connectome and genetics distances independent? --
No (reject null)
--- ### Distribution of distances are ordered
![:scale 50%](images/herit/distances.png)
--- ### Mann-Whitney test
P-value
MZ < DZ
1.647243e-02
MZ < Sibling
2.302542e-08
MZ < Unrelated
9.732951e-19
DZ < Sibling
1.042699e-02
DZ < Unrelated
1.154470e-08
Sibling < Unrelated
1.060595e-13
Caveat: samples are not independent --- ### What about confounders? - Studies show anatomical features are heritable - e.g. brain volume - Prior results explained by anatomy? --- ### Are the covariates themselves heritable? - Features: brain volume, four measurements of diffusivity - Covariate distance: $\delta_Z(z_i, z_j) = ||z_i - z_j||_F$ - DCorr(covariate distance, genetic distances) =
reject null
![:scale 40%](images/herit/covariate_dist.png)
--- ### Mann-Whitney test
P-values
MZ < DZ
1.074841e-02
MZ < Sibling
3.092601e-04
MZ < Unrelated
1.462330e-08
DZ < Sibling
3.345203e-01
DZ < Unrelated
4.825626e-03
Sibling < Unrelated
3.549662e-06
--- ### Conditional Distance Correlation (CDCorr) - Same as DCorr, but we now test $X \perp Y | Z$ - CDCorr(connectome distances, genetic distances | covariate distances) =
reject null
--- ### Finding “non-heritable” Induced Subgraph - Subgraph = graph formed from subset of vertices - Motivation: heritability explained by small subset of vertices? - Repeat CDCorr for each vertex, discard vertices with small p-value
![:scale 40%](images/herit/subgraph.png)
--- ### Mann-Whitney Test
P-value
MZ < DZ
4.237065e-01
MZ < Sibling
3.990682e-03
MZ < Unrelated
9.618273e-07
DZ < Sibling
6.148544e-03
DZ < Unrelated
1.987379e-06
Sibling < Unrelated
7.779698e-06
--- class: middle .center[questions?] --- ### Acknowledgements
Josh Vogelstein
Carey Priebe
Eric
Jesus
Jayanta
Ben
Alex
Ross